My solution to a “Daily Coding Problem” that I received in my mail today.

Given an array of integers, return a new array such that each element at index i of the new array is the product of all the numbers in the original array except the one at i.

For example, if our input was [1, 2, 3, 4, 5], the expected output would be [120, 60, 40, 30, 24]. If our input was [3, 2, 1], the expected output would be [2, 3, 6].

Follow-up: what if you can’t use division?

Here’s my non optimal solution in Javascript,

function product(inputArr) {
if(inputArr ===  null || inputArr === undefined) {
//return an empty array
return [];
}
let productArray = [];
for(let i=0; i < inputArr.length; i++) {
let product = 1;
for(let j=0; j < inputArr.length; j++) {
if( j === i) {
//if at the same index, we skip it
continue;
}
//what if there's a 0 value in the array?
product *= inputArr[j];
}
productArray[i] = product;
product = 1;
//or we can also do productArray[i] = product
}
return productArray;
}

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Categories: Javascript

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